Two uniform identical ladders AB and AC each of mass m leans against each other and a string is tied between them which is horizontal. The system stands on a smooth horizontal surface as shown, then, string is connected from ends B and C.
A
the force exerted by one rod on other at A is equal to the tension T in the string
B
tension in string T = 
cot θ
cot θ
C
tension in string T = 
tan θ
tan θ
D
None of these
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(a, b)
R= T …...(1)
N = mg…...(2)
taking torque about centre of mass
N × 
cos θ = R × 
sin θ + T × 
sin θ
∴ 
cos θ = T sin θ ⇒ T = 
cot θ
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